25x^2+45x+8=0

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Solution for 25x^2+45x+8=0 equation:



25x^2+45x+8=0
a = 25; b = 45; c = +8;
Δ = b2-4ac
Δ = 452-4·25·8
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-35}{2*25}=\frac{-80}{50} =-1+3/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+35}{2*25}=\frac{-10}{50} =-1/5 $

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